Trigonometry Guide

Special Right Triangles Explained

Learn the side-length patterns for \(45^\circ\text{-}45^\circ\text{-}90^\circ\) and \(30^\circ\text{-}60^\circ\text{-}90^\circ\) triangles, then use them to find missing sides and exact trigonometric values.

Special right triangles have side lengths that always follow the same patterns. Once you recognize the triangle, you can find missing sides without using a calculator.

There are two important families: the \(45^\circ\text{-}45^\circ\text{-}90^\circ\) triangle and the \(30^\circ\text{-}60^\circ\text{-}90^\circ\) triangle. These relationships also explain many of the exact values found on the unit circle.

The Big Idea

What Makes a Right Triangle Special?

Every right triangle contains one \(90^\circ\) angle, but most right triangles can have many different combinations of side lengths. Special right triangles are different because their angle measures force their sides to follow a fixed ratio.

This means that once you know one side, the other two sides can be found by multiplying or dividing by the appropriate part of the ratio.

Isosceles Right Triangle

\(45^\circ\text{-}45^\circ \text{-}90^\circ\)

\[ 1:1:\sqrt{2} \]

The two legs are equal. The hypotenuse is a leg multiplied by \(\sqrt{2}\).

Explore the 45-45-90 triangle

Half of an Equilateral Triangle

\(30^\circ\text{-}60^\circ \text{-}90^\circ\)

\[ 1:\sqrt{3}:2 \]

The short leg is opposite \(30^\circ\), and the long leg is opposite \(60^\circ\).

Explore the 30-60-90 triangle

Triangle Family 1

The 45-45-90 Triangle

A \(45^\circ\text{-}45^\circ\text{-}90^\circ\) triangle is an isosceles right triangle. Because the two acute angles are equal, the two legs opposite those angles must also be equal.

If each leg has length \(x\), the hypotenuse has length \(x\sqrt{2}\).

Visual Model

Equal Legs and a \(\sqrt{2}\) Hypotenuse

\[ x,\ x,\ x\sqrt{2} \]
Both legs are opposite \(45^\circ\) angles, so they have equal lengths.

First Leg

\(x\)

Opposite one \(45^\circ\) angle

Second Leg

\(x\)

Opposite the other \(45^\circ\) angle

Hypotenuse

\(x\sqrt{2}\)

Opposite the \(90^\circ\) angle

45

45-45-90 Rule

Leg, Leg, Hypotenuse

\[ x:x:x\sqrt{2} \]
  • Multiply a leg by \(\sqrt{2}\) to find the hypotenuse.
  • Divide the hypotenuse by \(\sqrt{2}\) to find a leg.
  • The two legs always have the same length.

Worked Example 1

Find the Hypotenuse

Foundation

A \(45^\circ\text{-}45^\circ \text{-}90^\circ\) triangle has a leg of length \(7\). Find the hypotenuse.

  1. Identify the triangle.

    The angles are \(45^\circ\), \(45^\circ\), and \(90^\circ\).

  2. Start with the ratio.
    \[ x:x:x\sqrt{2} \]
  3. Substitute \(7\) for \(x\).
    \[ h=7\sqrt{2} \]
Answer \[ \boxed{7\sqrt{2}} \]

Worked Example 2

Find a Leg from the Hypotenuse

Intermediate

The hypotenuse of a \(45^\circ\text{-}45^\circ \text{-}90^\circ\) triangle is \(12\). Find the length of each leg.

Use the hypotenuse rule \[ x\sqrt{2}=12 \]
Divide by \(\sqrt{2}\) \[ x=\frac{12}{\sqrt{2}} \]
Rationalize and simplify \[ x= \frac{12\sqrt{2}}{2} = 6\sqrt{2} \]
Answer \[ \boxed{6\sqrt{2}} \]

Triangle Family 2

The 30-60-90 Triangle

A \(30^\circ\text{-}60^\circ \text{-}90^\circ\) triangle can be created by cutting an equilateral triangle in half. Its three side lengths always follow the ratio \(1:\sqrt{3}:2\).

Unlike a \(45^\circ\text{-}45^\circ \text{-}90^\circ\) triangle, the two legs are not equal. You must identify the short leg and long leg by looking at the angles opposite them.

Visual Model

Match Each Side with Its Opposite Angle

\[ x,\ x\sqrt{3},\ 2x \]
The shortest side is opposite \(30^\circ\), and the longest side is opposite \(90^\circ\).

Short Leg

\(x\)

Opposite the \(30^\circ\) angle

Long Leg

\(x\sqrt{3}\)

Opposite the \(60^\circ\) angle

Hypotenuse

\(2x\)

Opposite the \(90^\circ\) angle

30

30-60-90 Rule

Short, Long, Hypotenuse

\[ x:x\sqrt{3}:2x \]
  • Double the short leg to find the hypotenuse.
  • Multiply the short leg by \(\sqrt{3}\) to find the long leg.
  • Divide the hypotenuse by \(2\) to find the short leg.

Worked Example 3

Start with the Short Leg

Foundation

A \(30^\circ\text{-}60^\circ \text{-}90^\circ\) triangle has a short leg of length \(5\). Find the long leg and the hypotenuse.

  1. Identify the short leg.

    The side opposite \(30^\circ\) is the short leg, so \(x=5\).

  2. Find the long leg.
    \[ x\sqrt{3} = 5\sqrt{3} \]
  3. Find the hypotenuse.
    \[ 2x = 2(5) = 10 \]
Answer \[ \boxed{ 5\sqrt{3} \text{ and } 10 } \]

Worked Example 4

Start with the Long Leg

Intermediate

The long leg of a \(30^\circ\text{-}60^\circ \text{-}90^\circ\) triangle is \(9\sqrt{3}\). Find the short leg and hypotenuse.

Match the long leg \[ x\sqrt{3} = 9\sqrt{3} \]
Solve for \(x\) \[ x=9 \]
Double the short leg \[ 2x = 2(9) = 18 \]
Answer \[ \boxed{ \begin{aligned} \text{short leg} &= 9 \\[4pt] \text{hypotenuse} &= 18 \end{aligned} } \]

Worked Example 5

Start with the Hypotenuse

Intermediate

The hypotenuse of a \(30^\circ\text{-}60^\circ \text{-}90^\circ\) triangle is \(14\). Find both legs.

The hypotenuse is \(2x\) \[ 2x=14 \]
Find the short leg \[ x=7 \]
Find the long leg \[ x\sqrt{3} = 7\sqrt{3} \]
Answer \[ \boxed{ \text{short leg}=7, \qquad \text{long leg}=7\sqrt{3} } \]

A Reliable Process

How to Find Missing Side Lengths

Do not begin by multiplying numbers immediately. First identify the triangle family and determine which side length you have been given.

1

Identify the Angles

Decide whether the triangle is \(45\text{-}45\text{-}90\) or \(30\text{-}60\text{-}90\).

2

Label the Side Types

Mark the legs and hypotenuse. For a \(30\text{-}60\text{-}90\) triangle, also identify the short and long legs.

3

Write the Ratio

Write the appropriate side ratio before substituting the known length.

4

Solve and Simplify

Solve for \(x\), simplify radicals, and include units when the problem provides them.

Decision Guide

What Operation Should You Use?

Triangle Known Side Side to Find Operation
\(45\text{-}45 \text{-}90\) Leg Hypotenuse Multiply by \(\sqrt{2}\)
\(45\text{-}45 \text{-}90\) Hypotenuse Leg Divide by \(\sqrt{2}\)
\(30\text{-}60 \text{-}90\) Short leg Long leg Multiply by \(\sqrt{3}\)
\(30\text{-}60 \text{-}90\) Short leg Hypotenuse Multiply by \(2\)
\(30\text{-}60 \text{-}90\) Hypotenuse Short leg Divide by \(2\)
\(30\text{-}60 \text{-}90\) Long leg Short leg Divide by \(\sqrt{3}\)

The Trigonometry Connection

Special Triangles Create Exact Trigonometric Values

The exact sine and cosine values for \(30^\circ\), \(45^\circ\), and \(60^\circ\) come directly from special right triangles.

To see the connection, scale each special triangle so its hypotenuse equals \(1\). The horizontal leg becomes cosine, and the vertical leg becomes sine.

Visual Connection

From Triangle Sides to Unit Circle Coordinates

\[ P=(\cos\theta,\sin\theta) \]
The coordinate of each point is \((\cos\theta,\sin\theta)\).

Exact Values

First-Quadrant Special Angles

These values should be understood from the triangle ratios rather than treated as unrelated facts.

Angle Triangle \(\sin\theta\) \(\cos\theta\) \(\tan\theta\)
\(30^\circ\) \(30\text{-}60 \text{-}90\) \(\dfrac{1}{2}\) \(\dfrac{\sqrt{3}}{2}\) \(\dfrac{\sqrt{3}}{3}\)
\(45^\circ\) \(45\text{-}45 \text{-}90\) \(\dfrac{\sqrt{2}}{2}\) \(\dfrac{\sqrt{2}}{2}\) \(1\)
\(60^\circ\) \(30\text{-}60 \text{-}90\) \(\dfrac{\sqrt{3}}{2}\) \(\dfrac{1}{2}\) \(\sqrt{3}\)

Worked Example 6

Find an Exact Trigonometric Value

Application

Use a special right triangle to find the exact value of \(\sin 60^\circ\).

  1. Use the \(30\text{-}60 \text{-}90\) ratio.
    \[ 1:\sqrt{3}:2 \]
  2. Identify the side opposite \(60^\circ\).

    The opposite side is the long leg, so its length is \(\sqrt{3}\).

  3. Use sine.
    \[ \sin 60^\circ = \frac{\text{opposite}} {\text{hypotenuse}} = \frac{\sqrt{3}}{2} \]
Answer \[ \boxed{ \frac{\sqrt{3}}{2} } \]

Check Your Reasoning

Avoid Common Special Triangle Mistakes

Most mistakes happen because a side is matched with the wrong part of the ratio. Label the angles and side types before calculating.

Mixing Up the Ratios

The ratio \(1:1:\sqrt{2}\) belongs to a \(45\text{-}45\text{-}90\) triangle.

Remember: equal angles create equal legs.

Reversing the Legs

In a \(30\text{-}60\text{-}90\) triangle, \(x\) is opposite \(30^\circ\), not \(60^\circ\).

Remember: the smallest angle faces the shortest side.

Using the Wrong Direction

If the hypotenuse is known, you usually divide to work backward toward the basic value \(x\).

Remember: solve for \(x\) before finding the remaining sides.

Leaving Radicals Unsimplified

An answer such as \(\sqrt{72}\) should be simplified before it is treated as a final answer.

\[ \sqrt{72} = 6\sqrt{2} \]

Ready to Practice?

Strengthen the Two Triangle Patterns

Practice identifying special triangles, matching sides with angles, finding missing lengths, simplifying radicals, and using the ratios to find exact trigonometric values.

Keep These Nearby

\(45\text{-}45 \text{-}90\) \[ 1:1:\sqrt{2} \]
\(30\text{-}60 \text{-}90\) \[ 1:\sqrt{3}:2 \]

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