Power Rule
Bring down the exponent and subtract one.
Calculus Practice
Practice derivative notation, the power rule, product rule, quotient rule, chain rule, trig derivatives, tangent lines, and differentiability.
Try each problem first, then click Show solution to check your work and see the complete step-by-step solution.
Keep These Rules Nearby
Bring down the exponent and subtract one.
Differentiate one factor at a time.
Differentiate the outside, then multiply by the derivative of the inside.
Level 1
Start with derivative notation, constants, and simple power-rule derivatives.
Problem 1
Derivative MeaningStep-by-Step Solution
A derivative evaluated at a point gives the instantaneous rate of change there.
Geometrically, it is the slope of the tangent line.
Problem 2
Constant RuleStep-by-Step Solution
A constant does not change as \(x\) changes.
Problem 3
Power RuleStep-by-Step Solution
Apply the power rule:
Level 2
Differentiate term by term and work with negative and fractional exponents.
Problem 4
PolynomialStep-by-Step Solution
Differentiate each term.
Problem 5
Negative ExponentStep-by-Step Solution
Apply the power rule.
With positive exponents,
\[ -3x^{-4} = -\frac{3}{x^4}. \]Problem 6
RadicalStep-by-Step Solution
Rewrite the square root using an exponent.
Rewrite using a radical:
\[ \frac12x^{-1/2} = \frac{1}{2\sqrt{x}}. \]Level 3
Differentiate products and quotients of functions without treating the operations term by term.
Problem 7
Product RuleStep-by-Step Solution
Use the product rule:
\[ (fg)'=f'g+fg'. \]Let
\[ f=x^2, \qquad g=x^3+1. \] \[ f'=2x, \qquad g'=3x^2. \]Problem 8
Product RuleStep-by-Step Solution
Let
\[ f=x^3, \qquad g=\sin x. \] \[ f'=3x^2, \qquad g'=\cos x. \]Problem 9
Quotient RuleStep-by-Step Solution
Use the quotient rule:
\[ \left( \frac{f}{g} \right)' = \frac{ f'g-fg' }{ g^2 }. \]Here,
\[ f=x^2+1, \qquad g=x. \] \[ f'=2x, \qquad g'=1. \]Level 4
Differentiate composite functions and combine the chain rule with trigonometric derivatives.
Problem 10
Chain RuleStep-by-Step Solution
Differentiate the outer power first.
\[ 5(3x^2+1)^4 \]Then multiply by the derivative of the inside:
\[ \frac{d}{dx}(3x^2+1) = 6x. \]Problem 11
Trig DerivativeStep-by-Step Solution
Recall:
\[ (\sin x)'=\cos x \] \[ (\cos x)'=-\sin x. \]Problem 12
Trig + Chain RuleStep-by-Step Solution
Differentiate the outer sine function.
\[ \sin(u) \longrightarrow \cos(u) \]Keep the inside unchanged:
\[ \cos(4x^2). \]Now multiply by the derivative of \(4x^2\).
\[ \frac{d}{dx}(4x^2) = 8x. \]Problem 13
Chain RuleStep-by-Step Solution
Differentiate cosine:
\[ \cos(u) \longrightarrow -\sin(u). \]Then multiply by the derivative of \(5x\):
\[ \frac{d}{dx}(5x)=5. \]Level 5
Use derivatives geometrically and combine multiple derivative concepts.
Problem 14
Tangent SlopeStep-by-Step Solution
Differentiate:
\[ f'(x)=2x. \]Evaluate at \(x=3\):
Problem 15
Tangent LineStep-by-Step Solution
First find the derivative.
\[ f'(x)=2x. \]Find the slope at \(x=2\):
\[ f'(2)=4. \]Find the point:
\[ f(2)=4. \]Use point-slope form:
Problem 16
DifferentiabilityStep-by-Step Solution
The graph of \(y=|x|\) has a sharp corner at \(x=0\).
From the left, the slope is
\[ -1. \]From the right, the slope is
\[ 1. \]Since the one-sided slopes do not agree, there is no single tangent slope.
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