Geometric Series
Only use the infinite sum formula when \(|r|<1\).
Calculus Practice
Practice sequence limits, infinite series, convergence tests, power series, and Taylor and Maclaurin series.
Try each problem first, then click Show solution to check your work and reasoning.
Keep These Rules Nearby
Only use the infinite sum formula when \(|r|<1\).
If \(p\leq1\), the series diverges.
\(L<1\): converges. \(L>1\): diverges.
Level 1
Practice sequence notation, sequence limits, common patterns, and geometric series.
Problem 1
Sequence TermsStep-by-Step Solution
Substitute each value of \(n\).
Problem 2
Sequence LimitStep-by-Step Solution
Divide the numerator and denominator by \(n\).
Problem 3
Geometric SequenceStep-by-Step Solution
Divide each term by the previous term.
\[ \frac{10}{5} = \frac{20}{10} = \frac{40}{20} = 2. \]Problem 4
Infinite Geometric SeriesStep-by-Step Solution
Here,
\[ a=6, \qquad r=\frac12. \]Since \(|r|<1\), the series converges.
Level 2
Use the nth-term test, geometric-series test, \(p\)-series test, and integral test.
Problem 5
nth-Term TestStep-by-Step Solution
Check the term limit.
\[ \lim_{n\to\infty} \frac{3n}{2n+1} = \frac32. \]Since the terms do not approach \(0\), the series diverges.
Problem 6
Harmonic SeriesStep-by-Step Solution
This is the harmonic series, which is a \(p\)-series with \(p=1\).
A \(p\)-series converges only when \(p>1\).
Problem 7
\(p\)-SeriesStep-by-Step Solution
This is a \(p\)-series with
\[ p=\frac52. \]Since \(\frac52>1\), it converges.
Problem 8
Integral TestStep-by-Step Solution
Consider
\[ f(x) = \frac{1}{x^2+1}. \]Then
\[ \int_1^\infty \frac{1}{x^2+1}\,dx = \lim_{b\to\infty} \left[ \arctan x \right]_1^b. \]The improper integral is finite, so the series converges.
Level 3
Compare with benchmark series and distinguish absolute from conditional convergence.
Problem 9
Direct ComparisonStep-by-Step Solution
For \(n\geq1\),
\[ 0 \lt \frac{1}{n^2+4} \lt \frac{1}{n^2}. \]Since \(\sum 1/n^2\) converges, the given series converges by direct comparison.
Problem 10
Limit ComparisonStep-by-Step Solution
Let
\[ a_n = \frac{4n+1}{n^2+3}, \qquad b_n = \frac1n. \]Since \(0 \lt 4 \lt \infty\), the two series have the same behavior.
The harmonic series diverges, so the given series diverges.
Problem 11
Alternating SeriesStep-by-Step Solution
Let
\[ b_n=\frac1n. \]The terms \(b_n\) decrease and
\[ \lim_{n\to\infty}b_n=0. \]Therefore the series converges by the Alternating Series Test.
Problem 12
Conditional ConvergenceStep-by-Step Solution
The alternating harmonic series converges.
But the absolute-value series is
\[ \sum_{n=1}^{\infty} \frac1n, \]which diverges.
Level 4
Practice tests designed for factorials, nth powers, and intervals of convergence.
Problem 13
Ratio TestStep-by-Step Solution
Since \(L<1\), the series converges absolutely.
Problem 14
Root TestStep-by-Step Solution
Since \(\frac23<1\), the series converges absolutely.
Problem 15
Interval of ConvergenceStep-by-Step Solution
Apply the ratio test:
\[ \left| \frac{ x^{n+1} }{ n+1 } \cdot \frac{ n }{ x^n } \right| = |x| \frac{n}{n+1}. \]Taking the limit gives
\[ |x| \lt 1. \]Now test endpoints.
At \(x=1\):
\[ \sum\frac1n \]diverges.
At \(x=-1\):
\[ \sum \frac{(-1)^n}{n} \]converges.
Level 5
Build and recognize polynomial series representations of functions.
Problem 16
Maclaurin PolynomialStep-by-Step Solution
The Maclaurin series for \(e^x\) is
\[ e^x = 1 + x + \frac{x^2}{2!} + \frac{x^3}{3!} + \cdots. \]Keep terms through degree \(3\).
Problem 17
Common SeriesStep-by-Step Solution
The cosine series uses even powers and alternating signs.
Problem 18
Geometric Power SeriesStep-by-Step Solution
Start with
\[ \frac{1}{1-r} = \sum_{n=0}^{\infty}r^n. \]Let \(r=-x\).
The geometric series requires
\[ |x| \lt 1. \]Before You Finish
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