Trigonometry Guide

Trigonometric Identities Explained

Learn the essential trigonometric identities and how to use them to rewrite, simplify, and verify trigonometric expressions.

Trigonometric Relationships

What Is a Trigonometric Identity?

A trigonometric identity is an equation involving trig functions that is true for every value for which both sides of the equation are defined.

Instead of treating identities as a long list of formulas to memorize, it is more useful to understand how the identities are connected and how one form can be rewritten as another.

Identity

An identity is not an equation that is true for only one particular value of \( \theta \). It represents a relationship that remains true throughout its domain.

Equation

\[ \sin\theta = \frac{1}{2} \]

This is true only for certain values of \( \theta \).

Identity

\[ \sin^2\theta + \cos^2\theta = 1 \]

This relationship is true for every angle where the expressions are defined.

Why This Matters

Identities Let You Rewrite Trig Expressions

The same trigonometric quantity can often be written in several different ways. That means a complicated-looking expression may become much easier once one part is replaced using an identity.

Start \[ \frac{\sin\theta} {\cos\theta} \]
Rewrite \[ \tan\theta \]

Learning trig identities is therefore less about memorizing isolated equations and more about recognizing equivalent forms.

The Essential Formulas

The Three Families of Trig Identities

Most introductory trig identity problems rely heavily on three groups: reciprocal identities, quotient identities, and Pythagorean identities.

Family 1

Reciprocal Identities

The reciprocal identities come from the fact that cosecant, secant, and cotangent are reciprocals of sine, cosine, and tangent.

Cosecant and Sine

\[ \csc\theta = \frac{1}{\sin\theta} \]
\[ \sin\theta = \frac{1}{\csc\theta} \]

Secant and Cosine

\[ \sec\theta = \frac{1}{\cos\theta} \]
\[ \cos\theta = \frac{1}{\sec\theta} \]

Cotangent and Tangent

\[ \cot\theta = \frac{1}{\tan\theta} \]
\[ \tan\theta = \frac{1}{\cot\theta} \]

Think “Flip”

Reciprocal identities are especially useful when you want to replace \(\sec\), \(\csc\), or \(\cot\) with expressions involving sine, cosine, or tangent.

Family 2

Quotient Identities

Tangent and cotangent can also be written as ratios involving sine and cosine.

Tangent

\[ \tan\theta = \frac{\sin\theta} {\cos\theta} \]

Tangent is sine divided by cosine.

Cotangent

\[ \cot\theta = \frac{\cos\theta} {\sin\theta} \]

Cotangent is cosine divided by sine.

Why This Is Useful

Rewrite Everything in Sine and Cosine

When a trig expression looks complicated, one of the most useful strategies is to rewrite tangent, cotangent, secant, and cosecant using sine and cosine.

Start \[ \frac{\tan\theta} {\sec\theta} \]
Rewrite \[ \frac{ \frac{\sin\theta}{\cos\theta} }{ \frac{1}{\cos\theta} } \]
Simplify \[ \sin\theta \]

Watch the Order

Tangent is \(\sin\theta/\cos\theta\), while cotangent is the reverse: \(\cos\theta/\sin\theta\).

Family 3

Pythagorean Identities

The Pythagorean identities are some of the most important identities in trigonometry.

The key is that you do not really need to think of them as three unrelated formulas. Start with one fundamental identity, and the other two can be derived from it.

Fundamental Identity

\[ \sin^2\theta + \cos^2\theta = 1 \]

Tangent-Secant Identity

\[ 1 + \tan^2\theta = \sec^2\theta \]

Cotangent-Cosecant Identity

\[ 1 + \cot^2\theta = \csc^2\theta \]

Where Does It Come From?

The Unit Circle Gives Us the Fundamental Identity

Recall that every point on the unit circle can be written as

\[ \left( \cos\theta, \sin\theta \right) \]

The equation of a circle centered at the origin with radius \(1\) is

\[ x^2+y^2=1 \]

On the unit circle,

\[ x=\cos\theta \]
\[ y=\sin\theta \]

Substitute these into the equation of the circle.

1
\[ x^2+y^2=1 \]
2
\[ (\cos\theta)^2 + (\sin\theta)^2 = 1 \]
3
\[ \boxed{ \sin^2\theta + \cos^2\theta = 1 } \]

Notation Reminder

\[ \sin^2\theta \] means \[ (\sin\theta)^2 \] It does not mean \[ \sin(\theta^2) \]

Derivation 1

Getting the Tangent-Secant Identity

Start with the fundamental Pythagorean identity.

\[ \sin^2\theta + \cos^2\theta = 1 \]

Divide every term by \(\cos^2\theta\).

\[ \frac{\sin^2\theta} {\cos^2\theta} + \frac{\cos^2\theta} {\cos^2\theta} = \frac{1} {\cos^2\theta} \]

Now use the quotient and reciprocal identities.

\[ \frac{\sin^2\theta} {\cos^2\theta} = \tan^2\theta \]
\[ \frac{\cos^2\theta} {\cos^2\theta} = 1 \]
\[ \frac{1} {\cos^2\theta} = \sec^2\theta \]
Therefore \[ \boxed{ 1+\tan^2\theta = \sec^2\theta } \]

Derivation 2

Getting the Cotangent-Cosecant Identity

Again, begin with

\[ \sin^2\theta + \cos^2\theta = 1 \]

This time, divide every term by \(\sin^2\theta\).

\[ \frac{\sin^2\theta} {\sin^2\theta} + \frac{\cos^2\theta} {\sin^2\theta} = \frac{1} {\sin^2\theta} \]

Simplify each term.

\[ \frac{\sin^2\theta} {\sin^2\theta} = 1 \]
\[ \frac{\cos^2\theta} {\sin^2\theta} = \cot^2\theta \]
\[ \frac{1} {\sin^2\theta} = \csc^2\theta \]
Therefore \[ \boxed{ 1+\cot^2\theta = \csc^2\theta } \]

See the Connection

One Identity Generates All Three

\[ \sin^2\theta + \cos^2\theta = 1 \]
Divide by \(\cos^2\theta\)
\[ 1+\tan^2\theta = \sec^2\theta \]
Divide by \(\sin^2\theta\)
\[ 1+\cot^2\theta = \csc^2\theta \]

If you forget one of the last two identities, you can reconstruct it from \[ \sin^2\theta+\cos^2\theta=1. \]

Family 4

Sum and Difference Identities

Sum and difference identities let you find trig values for angles that can be written as the sum or difference of two familiar angles.

They also form the foundation for several other identity families, including the double-angle formulas.

Sine of a Sum

\[ \sin(A+B) = \sin A\cos B + \cos A\sin B \]

Sine of a Difference

\[ \sin(A-B) = \sin A\cos B - \cos A\sin B \]

Sine Pattern

\[ \boxed{ \sin(A\pm B) = \sin A\cos B \pm \cos A\sin B } \]

Cosine of a Sum

\[ \cos(A+B) = \cos A\cos B - \sin A\sin B \]

Cosine of a Difference

\[ \cos(A-B) = \cos A\cos B + \sin A\sin B \]

Cosine Pattern

\[ \boxed{ \cos(A\pm B) = \cos A\cos B \mp \sin A\sin B } \]

Tangent of a Sum

\[ \tan(A+B) = \frac{ \tan A+\tan B }{ 1-\tan A\tan B } \]

Tangent of a Difference

\[ \tan(A-B) = \frac{ \tan A-\tan B }{ 1+\tan A\tan B } \]

Watch the Signs

Sine keeps the same sign as the angle operation. Cosine switches the sign. Tangent keeps the sign in the numerator and switches it in the denominator.

Example

Find the Exact Value of \(\sin 75^\circ\)

\[ \sin75^\circ = \sin(45^\circ+30^\circ) \]
1

Use the sine sum identity.

\[ \sin(A+B) = \sin A\cos B + \cos A\sin B \]
2

Substitute \(A=45^\circ\) and \(B=30^\circ\).

\[ \sin75^\circ = \sin45^\circ\cos30^\circ + \cos45^\circ\sin30^\circ \]
3

Substitute the exact trig values.

\[ = \left( \frac{\sqrt2}{2} \right) \left( \frac{\sqrt3}{2} \right) + \left( \frac{\sqrt2}{2} \right) \left( \frac12 \right) \]
4

Simplify.

\[ \boxed{ \sin75^\circ = \frac{ \sqrt6+\sqrt2 }{ 4 } } \]

Family 5

Double-Angle Identities

Double-angle identities are special cases of the sum identities where the two angles are the same.

In other words, replace \(A\) and \(B\) with \(\theta\).

From the Sine Sum Identity

Deriving the Sine Double-Angle Identity

\[ \sin(A+B) = \sin A\cos B + \cos A\sin B \]

Let \(A=B=\theta\).

\[ \sin(\theta+\theta) = \sin\theta\cos\theta + \cos\theta\sin\theta \]
Therefore \[ \boxed{ \sin(2\theta) = 2\sin\theta\cos\theta } \]

From the Cosine Sum Identity

Deriving the Cosine Double-Angle Identity

\[ \cos(A+B) = \cos A\cos B - \sin A\sin B \]

Again, let \(A=B=\theta\).

\[ \cos(2\theta) = \cos^2\theta - \sin^2\theta \]

Cosine Has Three Useful Forms

The Pythagorean identity lets us rewrite the cosine double-angle formula in two additional ways.

Form 1

\[ \cos(2\theta) = \cos^2\theta - \sin^2\theta \]

Form 2

\[ \cos(2\theta) = 2\cos^2\theta-1 \]

Form 3

\[ \cos(2\theta) = 1-2\sin^2\theta \]

From the Tangent Sum Identity

Tangent Double-Angle Identity

\[ \tan(A+B) = \frac{ \tan A+\tan B }{ 1-\tan A\tan B } \]

Let \(A=B=\theta\).

Therefore \[ \boxed{ \tan(2\theta) = \frac{ 2\tan\theta }{ 1-\tan^2\theta } } \]

Double-Angle Reference

The Formulas to Know

\[ \sin(2\theta) = 2\sin\theta\cos\theta \]
\[ \cos(2\theta) = \cos^2\theta-\sin^2\theta \]
\[ \tan(2\theta) = \frac{ 2\tan\theta }{ 1-\tan^2\theta } \]

Family 6

Half-Angle Identities

Half-angle identities let you work with trig functions of \(\theta/2\).

They come from rearranging the cosine double-angle identities.

From the Cosine Double-Angle Identity

Sine Half-Angle Identity

\[ \cos(2\alpha) = 1-2\sin^2\alpha \]

Solve for \(\sin^2\alpha\).

\[ 2\sin^2\alpha = 1-\cos(2\alpha) \] \[ \sin^2\alpha = \frac{ 1-\cos(2\alpha) }{ 2 } \]

Let \(2\alpha=\theta\), so \(\alpha=\theta/2\).

Therefore \[ \boxed{ \sin\left( \frac{\theta}{2} \right) = \pm \sqrt{ \frac{ 1-\cos\theta }{ 2 } } } \]

From the Cosine Double-Angle Identity

Cosine Half-Angle Identity

\[ \cos(2\alpha) = 2\cos^2\alpha-1 \]

Solve for \(\cos^2\alpha\).

\[ 2\cos^2\alpha = 1+\cos(2\alpha) \] \[ \cos^2\alpha = \frac{ 1+\cos(2\alpha) }{ 2 } \]

Again, let \(2\alpha=\theta\).

Therefore \[ \boxed{ \cos\left( \frac{\theta}{2} \right) = \pm \sqrt{ \frac{ 1+\cos\theta }{ 2 } } } \]

What Determines the \(\pm\)?

The sign is determined by the quadrant containing \(\theta/2\). Use the sign that matches the trig function in that quadrant.

Tangent Half Angle

Three Useful Forms

Square-Root Form

\[ \tan\left( \frac{\theta}{2} \right) = \pm \sqrt{ \frac{ 1-\cos\theta }{ 1+\cos\theta } } \]

Sine Over One Plus Cosine

\[ \tan\left( \frac{\theta}{2} \right) = \frac{ \sin\theta }{ 1+\cos\theta } \]

One Minus Cosine Over Sine

\[ \tan\left( \frac{\theta}{2} \right) = \frac{ 1-\cos\theta }{ \sin\theta } \]

Example

Find the Exact Value of \(\cos 15^\circ\)

\[ 15^\circ = \frac{ 30^\circ }{ 2 } \]
1

Use the cosine half-angle identity.

\[ \cos\left( \frac{\theta}{2} \right) = \pm \sqrt{ \frac{ 1+\cos\theta }{ 2 } } \]
2

Use \(\theta=30^\circ\). Since \(15^\circ\) is in Quadrant I, cosine is positive.

\[ \cos15^\circ = \sqrt{ \frac{ 1+\cos30^\circ }{ 2 } } \]
3

Substitute \(\cos30^\circ = \sqrt3/2\).

\[ \cos15^\circ = \sqrt{ \frac{ 1+\frac{\sqrt3}{2} }{ 2 } } \]
4

Simplify.

\[ \boxed{ \cos15^\circ = \frac{ \sqrt{ 2+\sqrt3 } }{ 2 } } \]

Family 7

Power-Reduction Identities

Power-reduction identities rewrite squared trig functions using first powers of sine or cosine.

They come directly from the cosine double-angle identities.

Sine Squared

\[ \boxed{ \sin^2\theta = \frac{ 1-\cos(2\theta) }{ 2 } } \]

Cosine Squared

\[ \boxed{ \cos^2\theta = \frac{ 1+\cos(2\theta) }{ 2 } } \]

Tangent Squared

\[ \boxed{ \tan^2\theta = \frac{ 1-\cos(2\theta) }{ 1+\cos(2\theta) } } \]

Where They Come From

Rearrange the Double-Angle Formulas

Start with \[ \cos(2\theta) = 1-2\sin^2\theta \]
\[ \sin^2\theta = \frac{ 1-\cos(2\theta) }{ 2 } \]
Start with \[ \cos(2\theta) = 2\cos^2\theta-1 \]
\[ \cos^2\theta = \frac{ 1+\cos(2\theta) }{ 2 } \]

Why “Power Reduction”?

These identities reduce a squared trig function to an expression involving a first-power cosine term. They become especially useful later in calculus when working with trig integrals.

Put Them to Work

Using Trigonometric Identities

Once you know the core identities, the next step is learning how to rearrange and combine them.

Strategy 1

Rearrange an Identity

The Pythagorean identities can be rewritten to isolate whichever trig expression you need.

From

\[ \sin^2\theta + \cos^2\theta = 1 \]
\[ \boxed{ \sin^2\theta = 1-\cos^2\theta } \]

Or

\[ \sin^2\theta + \cos^2\theta = 1 \]
\[ \boxed{ \cos^2\theta = 1-\sin^2\theta } \]

From

\[ 1+\tan^2\theta = \sec^2\theta \]
\[ \boxed{ \tan^2\theta = \sec^2\theta-1 } \]

From

\[ 1+\cot^2\theta = \csc^2\theta \]
\[ \boxed{ \cot^2\theta = \csc^2\theta-1 } \]

Look for a Matching Piece

If an expression contains \(1-\cos^2\theta\), think \(\sin^2\theta\). If it contains \(\sec^2\theta-1\), think \(\tan^2\theta\).

Strategy 2

Simplify by Rewriting

A useful identity can turn a complicated expression into something much simpler.

Example 1

Simplify

\[ \frac{ 1-\cos^2\theta }{ \sin\theta } \]
1

Recognize the Pythagorean form:

\[ 1-\cos^2\theta = \sin^2\theta \]
2

Substitute.

\[ \frac{ \sin^2\theta }{ \sin\theta } \]
3

Cancel one factor of \(\sin\theta\).

\[ \boxed{ \sin\theta } \]

Example 2

Simplify

\[ \frac{ \sec^2\theta-1 }{ \tan\theta } \]
1

Use the rearranged identity:

\[ \sec^2\theta-1 = \tan^2\theta \]
2

Substitute.

\[ \frac{ \tan^2\theta }{ \tan\theta } \]
3

Simplify.

\[ \boxed{ \tan\theta } \]

Strategy 3

Rewrite in Sine and Cosine

When you are unsure what to do, rewriting everything in terms of sine and cosine is often a strong first move.

Example 3

Simplify

\[ \frac{ \tan\theta }{ \sec\theta } \]
1

Rewrite tangent and secant.

\[ \tan\theta = \frac{ \sin\theta }{ \cos\theta } \] \[ \sec\theta = \frac{ 1 }{ \cos\theta } \]
2

Substitute.

\[ \frac{ \frac{ \sin\theta }{ \cos\theta } }{ \frac{ 1 }{ \cos\theta } } \]
3

Multiply by the reciprocal.

\[ \frac{ \sin\theta }{ \cos\theta } \cdot \cos\theta \]
4

Cancel \(\cos\theta\).

\[ \boxed{ \sin\theta } \]

Strategy Check

Which Identity Should You Look For?

1

See \(\sec\), \(\csc\), or \(\cot\)?

Consider a reciprocal identity.

2

See \(\tan\) or \(\cot\)?

Consider rewriting with sine and cosine.

3

See squares and a \(1\)?

Look for a Pythagorean identity.

4

Nothing obvious?

Rewrite everything in sine and cosine and simplify algebraically.

Proving Relationships

Verifying Trigonometric Identities

To verify an identity, you show that one side can be transformed into the other using valid identities and algebra.

The Main Rule

Work on One Side at a Time

Start with the more complicated side, rewrite and simplify it, and stop when it matches the other side.

Good Approach

Transform One Side

\[ \frac{ 1-\cos^2\theta }{ \sin\theta } \]
\[ \frac{ \sin^2\theta }{ \sin\theta } \]
\[ \sin\theta \]

Avoid This

Changing Both Sides at Once

If you manipulate both sides simultaneously, it becomes much harder to show that one side truly transforms into the other.

Do not treat identity verification like solving an equation for a variable.

A Reliable Process

How to Verify an Identity

1

Choose the More Complicated Side

Start where there is more to simplify.

2

Look for Known Identities

Check for reciprocal, quotient, and Pythagorean forms.

3

Use Algebra

Factor, combine fractions, cancel common factors, or simplify powers.

4

Stop When the Other Side Appears

Once your transformed side matches the untouched side, the identity is verified.

Verification Example 1

Verify the Identity

\[ \frac{ 1-\cos^2\theta }{ \sin\theta } = \sin\theta \]
1

Work only on the left side.

\[ \frac{ 1-\cos^2\theta }{ \sin\theta } \]
2

Use \(1-\cos^2\theta = \sin^2\theta\).

\[ \frac{ \sin^2\theta }{ \sin\theta } \]
3

Simplify.

\[ \sin\theta \]
The left side simplified to the right side, so the identity is verified.

Verification Example 2

Verify the Identity

\[ \tan\theta\cos\theta = \sin\theta \]
1

Begin with the left side.

\[ \tan\theta\cos\theta \]
2

Rewrite tangent using the quotient identity.

\[ \frac{ \sin\theta }{ \cos\theta } \cos\theta \]
3

Cancel \(\cos\theta\).

\[ \sin\theta \]
The left side matches the right side.

Verification Example 3

Verify the Identity

\[ \frac{ \sec^2\theta-1 }{ \tan\theta } = \tan\theta \]
1

Start with the left side.

\[ \frac{ \sec^2\theta-1 }{ \tan\theta } \]
2

Use the Pythagorean identity \(\sec^2\theta-1 = \tan^2\theta\).

\[ \frac{ \tan^2\theta }{ \tan\theta } \]
3

Simplify.

\[ \tan\theta \]
The identity is verified.

If You Get Stuck

Try rewriting everything in sine and cosine. It is not always the shortest method, but it often reveals factors that cancel or combine.

Watch Out

Common Trigonometric Identity Mistakes

Most identity mistakes come from algebra, notation, or using the correct identity in the wrong way.

Mixing Up Tangent and Cotangent

Remember:

\[ \tan\theta = \frac{\sin\theta}{\cos\theta} \] \[ \cot\theta = \frac{\cos\theta}{\sin\theta} \]

Misreading Squared Notation

The expression \(\sin^2\theta\) means \((\sin\theta)^2\), not \(\sin(\theta^2)\).

Forgetting to Use Every Term

When dividing a Pythagorean identity by \(\sin^2\theta\) or \(\cos^2\theta\), divide every term in the equation.

Cancelling Across Addition

You can cancel common factors, but not individual pieces of terms that are being added or subtracted.

Working on Both Sides

When verifying an identity, simplify one side until it becomes the other side.

Forcing the Wrong Identity

If an identity does not immediately help, try another form or rewrite the expression in sine and cosine.

Quick Reference

Essential Trigonometric Identities

Reciprocal

\[ \csc\theta = \frac{1}{\sin\theta} \] \[ \sec\theta = \frac{1}{\cos\theta} \] \[ \cot\theta = \frac{1}{\tan\theta} \]

Quotient

\[ \tan\theta = \frac{\sin\theta}{\cos\theta} \] \[ \cot\theta = \frac{\cos\theta}{\sin\theta} \]

Pythagorean

\[ \sin^2\theta + \cos^2\theta = 1 \] \[ 1+\tan^2\theta = \sec^2\theta \] \[ 1+\cot^2\theta = \csc^2\theta \]

Before You Practice

Trigonometric Identities Checklist

  1. Know the reciprocal identities.
  2. Know the quotient identities.
  3. Know \(\sin^2\theta+\cos^2\theta=1\).
  4. Understand how the other two Pythagorean identities are derived.
  5. Look for useful rearranged forms.
  6. Rewrite in sine and cosine when stuck.
  7. When verifying an identity, work on one side at a time.
  8. Use algebra carefully when factoring, cancelling, and combining fractions.

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